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acceleration cannot be calculated from these values alone unless one makes a few assumptions:

Vf=final velocity

Vi=initial velocity

a=acceleration

d=displacement

t=time

assume Vi=0

(Vf-Vi)/t=a

Vf=at+Vi

Vf**2=Vi**2+2ad

(at)**2=2ad

aatt=2ad

att=2d

a=2d/t**2

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Q: How is acceleration related to the distance and time elapsed?
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How are acceleration and speed alike?

They are not alike but they are related. A positive acceleration means an increase in velocity (speed). A negative acceleration means a decrease in velocity. Velocity (speed) has the dimensions of distance / time. Acceleration has the dimensions of distance/time2 or velocity/time.


How is time acceleration velocity and distance?

You mean how are they related? Sting from rest condition, let V = velocity, T = time, S = distance, A = acceleration V = AT S = 1/2 AT^2 If there is no acceleration, at constant velocity S = VT


How do you find time when given distance and acceleration?

Distance = (1/2 of acceleration) x (time squared)You can change this around to solve it for acceleration or time.(Time squared) = (distance)/(half of acceleration)Time = the square root of [ (2 x distance)/(acceleration) ]Be careful . . .This is only true if the distance and the speed are both zero when the time begins.


When radius and height and distance is given how to find magnitude of centripetal acceleration?

There is no information that shows any relationship with time. Since acceleration is a variable related to time, it is impossible to answer the question.


Why the second is squared in acceleration?

it is very simple........... velocity or speed = distance / time. acceleration = velocity / time but, we know that velocity = distance / time so just substitute the equation of velocity in acceleration...... so, finally we get , acceleration = distance/time*time so it is time squared.

Related questions

How does distance vary with the square of time?

For a free-falling object, you can calculate the total distance traveled, given the amount of time. The distance of the fall is proportional to the square of the time elapsed. In general, distance can be found by the relationship between acceleration and time squared. If we let a be acceleration, which can be gravity if you want, and t be time, then we have: The distance traveled = 1/2 * a * t2 The distance traveled = 1/2 * g* t2


What is the equation relating acceleration the distance traveled and the time of fall.?

The equation relating acceleration, distance traveled, and time of fall is given by: distance = (1/2) * acceleration * time^2. This equation is derived from the kinematic equation for motion under constant acceleration.


How are acceleration and speed alike?

They are not alike but they are related. A positive acceleration means an increase in velocity (speed). A negative acceleration means a decrease in velocity. Velocity (speed) has the dimensions of distance / time. Acceleration has the dimensions of distance/time2 or velocity/time.


Is the velocity of an object always proportional to elapsed time?

No, the velocity of an object is not always proportional to elapsed time. Velocity is defined as the rate of change of an object's position with respect to time, so it can vary depending on factors like acceleration, deceleration, or changes in direction.


How is time acceleration velocity and distance?

You mean how are they related? Sting from rest condition, let V = velocity, T = time, S = distance, A = acceleration V = AT S = 1/2 AT^2 If there is no acceleration, at constant velocity S = VT


How do you find time when given distance and acceleration?

Distance = (1/2 of acceleration) x (time squared)You can change this around to solve it for acceleration or time.(Time squared) = (distance)/(half of acceleration)Time = the square root of [ (2 x distance)/(acceleration) ]Be careful . . .This is only true if the distance and the speed are both zero when the time begins.


How do you calculate acceleration from distance and time?

Acceleration= Distance/time (distance divided by time) That's the dumbest answer I've ever heard.. Acceleration = Final Velocity - Initial Velocity/Time Velocity = Displacement/Time So you can't calculate acceleration from distance and time, you can only do velocity.


When radius and height and distance is given how to find magnitude of centripetal acceleration?

There is no information that shows any relationship with time. Since acceleration is a variable related to time, it is impossible to answer the question.


What is the relationship between acceleration velocity time and distance?

Velocity is the derivative of position with respect to time (v = dx/dt). Acceleration is the derivative of velocity with respect to time (a = dv/dt) and therefore the second derivative of position with respect to time (a = d2v/dt2). A derivative basically refers to the "rate of change" - graphically, it is the slope on a curve.


How do you get the acceleration of an object?

Acceleration= Distance divided by time


Why the second is squared in acceleration?

it is very simple........... velocity or speed = distance / time. acceleration = velocity / time but, we know that velocity = distance / time so just substitute the equation of velocity in acceleration...... so, finally we get , acceleration = distance/time*time so it is time squared.


How would you find the average speed of an cyclist during an entire race?

Find the distance of the race. Find the cyclist's start time. Find the cyclist's finish time. Elapsed time = Finish time - Start time. Average speed = Distance/Elapsed time.