acceleration cannot be calculated from these values alone unless one makes a few assumptions:
Vf=final velocity
Vi=initial velocity
a=acceleration
d=displacement
t=time
assume Vi=0
(Vf-Vi)/t=a
Vf=at+Vi
Vf**2=Vi**2+2ad
(at)**2=2ad
aatt=2ad
att=2d
a=2d/t**2
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They are not alike but they are related. A positive acceleration means an increase in velocity (speed). A negative acceleration means a decrease in velocity. Velocity (speed) has the dimensions of distance / time. Acceleration has the dimensions of distance/time2 or velocity/time.
You mean how are they related? Sting from rest condition, let V = velocity, T = time, S = distance, A = acceleration V = AT S = 1/2 AT^2 If there is no acceleration, at constant velocity S = VT
Distance = (1/2 of acceleration) x (time squared)You can change this around to solve it for acceleration or time.(Time squared) = (distance)/(half of acceleration)Time = the square root of [ (2 x distance)/(acceleration) ]Be careful . . .This is only true if the distance and the speed are both zero when the time begins.
There is no information that shows any relationship with time. Since acceleration is a variable related to time, it is impossible to answer the question.
it is very simple........... velocity or speed = distance / time. acceleration = velocity / time but, we know that velocity = distance / time so just substitute the equation of velocity in acceleration...... so, finally we get , acceleration = distance/time*time so it is time squared.