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acceleration cannot be calculated from these values alone unless one makes a few assumptions:

Vf=final velocity

Vi=initial velocity

a=acceleration

d=displacement

t=time

assume Vi=0

(Vf-Vi)/t=a

Vf=at+Vi

Vf**2=Vi**2+2ad

(at)**2=2ad

aatt=2ad

att=2d

a=2d/t**2

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Q: How is acceleration related to the distance and time elapsed?
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How are acceleration and speed alike?

They are not alike but they are related. A positive acceleration means an increase in velocity (speed). A negative acceleration means a decrease in velocity. Velocity (speed) has the dimensions of distance / time. Acceleration has the dimensions of distance/time2 or velocity/time.


How is time acceleration velocity and distance?

You mean how are they related? Sting from rest condition, let V = velocity, T = time, S = distance, A = acceleration V = AT S = 1/2 AT^2 If there is no acceleration, at constant velocity S = VT


How do you find time when given distance and acceleration?

Distance = (1/2 of acceleration) x (time squared)You can change this around to solve it for acceleration or time.(Time squared) = (distance)/(half of acceleration)Time = the square root of [ (2 x distance)/(acceleration) ]Be careful . . .This is only true if the distance and the speed are both zero when the time begins.


When radius and height and distance is given how to find magnitude of centripetal acceleration?

There is no information that shows any relationship with time. Since acceleration is a variable related to time, it is impossible to answer the question.


Why the second is squared in acceleration?

it is very simple........... velocity or speed = distance / time. acceleration = velocity / time but, we know that velocity = distance / time so just substitute the equation of velocity in acceleration...... so, finally we get , acceleration = distance/time*time so it is time squared.