There is no information that shows any relationship with time. Since acceleration is a variable related to time, it is impossible to answer the question.
Its acceleration is always the same - the acceleration of gravity at 32 ft/sec/sec - no matter what distance it is during drop, until it hits the ground.
The measurement of 12 feet up is a scalar measurement. Scalars have magnitude but no direction. In this case, the magnitude is 12 feet, indicating the distance or height, but there is no direction specified.
Formula for working out height of a tree is (distance from eye to base of tree/distance from eye to base of stick) x length of stick = tree height.(distance from eye to base of tree/distance from eye to base of stick) x length of stick = tree height is the formula for working out height of a tree.
Mass, height, and acceleration due to gravity.
"the higher the altitude the lower the range "
I don't think you have enough information. Here are two formulae to calculate centripetal acceleration: a = v2 / r a = omega2 x r (omega is the angular speed, in radians per second) Basically, apart from the radius you also need to know (or have enough information to calculate) the speed (or equivalently, the angular speed).
Its acceleration is always the same - the acceleration of gravity at 32 ft/sec/sec - no matter what distance it is during drop, until it hits the ground.
You can drop an object from a certain height and time it to see how fast it goes. Make sure that you find the distance of the height from where you dropped it so that you can find out the speed by dividing the time by the distance.
Assuming (a) an initial velocity of zero, and (b) constant acceleration, the formula becomes: distance = 0.5 at2 (distance = 1/2 times acceleration times time squared).
The distance from the epicenter significantly affects the magnitude height of seismograph readings, as seismic waves diminish in amplitude as they travel through the Earth. The farther a seismograph is from the epicenter, the lower the recorded magnitude will generally be, due to the spreading of energy over a larger area and absorption by geological materials. Consequently, seismographs closer to the epicenter typically register higher magnitude readings than those located further away.
No, height is a scalar quantity, not a vector. Scalars have only magnitude, while vectors have both magnitude and direction. Height only gives the measurement of how tall something is, without specifying a direction.
The distance a rubber ball falls in 10 seconds will depend on the height from which it is dropped and the acceleration due to gravity. On Earth, neglecting air resistance, the general equation to calculate the distance fallen is: distance = 0.5 * acceleration due to gravity * time^2.
the gravitational pull makes the object fall quicker. it doesn't matter about weith
The solution to the Ferris wheel physics problem involves using equations of motion to calculate the height, speed, and acceleration of the riders on the Ferris wheel at different points in time. This can be done by considering the circular motion of the Ferris wheel and applying principles of centripetal acceleration and gravitational force.
The measurement of 12 feet up is a scalar measurement. Scalars have magnitude but no direction. In this case, the magnitude is 12 feet, indicating the distance or height, but there is no direction specified.
The seismograph reading tends to decrease in magnitude as the distance from the epicenter of an earthquake increases. This is because seismic waves lose intensity and amplitude as they travel through the Earth's crust, resulting in a weaker signal being recorded at farther distances from the epicenter.
To calculate an object's gravitational potential energy, you need to know the object's mass, the acceleration due to gravity, and the height at which the object is located above a reference point. The formula for gravitational potential energy is PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object.