10
If you have 20 tens you have 200. You don't need the rest.
Counting from the left, the first is ten times the second.
Well, isn't that a happy little question! If you have 3 tens, that's 30, and if you add 3 fives, that's another 15. So in total, you have 45. Just imagine all the wonderful things you could buy with that!
The 10s and 5s
10
9
it all depends how do you want type of bills you use like ones, fives, tens and so on
5/10 is greater
Yes.
You might be counting by pairs, threes, fours, or even fives. Sometimes, the numbers of the crowds of people are estimated by the busloads.
Oh, dude, let me grab my calculator... just kidding. So, there are 11 twenties in 56 fives. It's like basic math, but hey, who's counting, right?
If you have 20 tens you have 200. You don't need the rest.
To solve this problem, we first calculate the sum of 2 tens and 10 twos: 2 tens = 20, 10 twos = 20, so the sum is 20 + 20 = 40. Next, we determine how many fives are equal to 40 by dividing 40 by 5, which equals 8. Therefore, there are 8 fives that have the same value as the sum of 2 tens and 10 twos.
Counting from the left, the first is ten times the second.
Well, isn't that a happy little question! If you have 3 tens, that's 30, and if you add 3 fives, that's another 15. So in total, you have 45. Just imagine all the wonderful things you could buy with that!
Skip-counting can be useful when you want to quickly determine the total number of items in an array that are evenly spaced or follow a specific pattern, such as counting by twos, fives, or tens. For example, if you have an array of even numbers or multiples of a certain number, skip-counting allows you to efficiently calculate the total by counting only the significant intervals rather than each individual item. This method enhances efficiency and can simplify calculations in various mathematical contexts.