Want this question answered?
Roughly speaking, finding the third quartile is similar to finding the median. First, use the median to split the data set into two equal halves. Then the third quartile is the median of the upper half. Similarly, the first quartile is the median of the lower half.
The median of the first 7 is the fourth prime = 7.The median of the first 7 is the fourth prime = 7.The median of the first 7 is the fourth prime = 7.The median of the first 7 is the fourth prime = 7.
you are suppose to order them from least to greatest first then make your line graph
By finding a pattern the first time you solve a problem, then applying this pattern (algorithm) to solve similar problems.
You need to find the median first. That will divide the data into two halves. The median is also known as Q2 or second quartile. Now take the first half of you data and find the median of that half. This is known as Q1. Do the same with the second half and that is Q3. You box has Q1 on the left, Q3 on the right and Q2 in the middle. The whiskers will be the range of your data, that is to say the upper and lower extremes. You will graph the quartiles and the extremes with the scale underneath them. A link with pictures is provided. The 5 numbers, Q1, Q2, Q3 and the extremes(max and min values) are known as the 5 number summary.
Roughly speaking, finding the third quartile is similar to finding the median. First, use the median to split the data set into two equal halves. Then the third quartile is the median of the upper half. Similarly, the first quartile is the median of the lower half.
Ohms
37
A box plot summarises 5 key indicators of a distribution: the median, minimum, maximum and the lower and upper quartiles. The first of these is a measure of the central tendency whereas the others, in pairs, give measures of the spread as well as skewness.
The median of the first 7 is the fourth prime = 7.The median of the first 7 is the fourth prime = 7.The median of the first 7 is the fourth prime = 7.The median of the first 7 is the fourth prime = 7.
If this is the only information you have, the answer would be somewhere around 125. Usually, you would find the third quartile by first finding the median. Then find the median of all of the numbers between the median and the largest number, which is the third quartile.
you are suppose to order them from least to greatest first then make your line graph
The Casio fx-115 ES is a scientific calculator which you can use to calculate the first and third quartiles of a data set. To calculate the first and third quartiles, you first need to arrange the data set in ascending or descending order. Once the data set is arranged, you can use the following steps to calculate the first and third quartiles: Enter the data set into the calculator by pressing the Data/Matrix button. Once the data set is entered, press the STAT button and then the VARS button. Select the data set by pressing the number key that corresponds to the data set. Access the QUARTILE option by pressing the 5 key. Enter the number 1 to calculate the first quartile or enter the number 3 to calculate the third quartile. The calculator will display the first or third quartile of the data set. These steps can be used to calculate the first and third quartiles on a Casio fx-115 ES.
By finding a pattern the first time you solve a problem, then applying this pattern (algorithm) to solve similar problems.
You need to find the median first. That will divide the data into two halves. The median is also known as Q2 or second quartile. Now take the first half of you data and find the median of that half. This is known as Q1. Do the same with the second half and that is Q3. You box has Q1 on the left, Q3 on the right and Q2 in the middle. The whiskers will be the range of your data, that is to say the upper and lower extremes. You will graph the quartiles and the extremes with the scale underneath them. A link with pictures is provided. The 5 numbers, Q1, Q2, Q3 and the extremes(max and min values) are known as the 5 number summary.
First, I will give an example, similar to your question: -11000 -9000 +44000 mean = 8,000 and median = -9000. Symmetrical distributions after infinite sampling will show no difference in mean and median. Large differences are possible with small sample sizes even with symmetrical distributions. If the sample is large and the difference is large, this infers that the distribution is asymmetrical. The skewness of the distribution can be calculated.
2,3,5,7,11, Are the first five prime numbers. Their median is the absolute middle , which is '5'.