Easy. If you have a line graph and you, say, are doing a graph on how many fruits are eaten in a month. Then lemons could be low while melons are high, then they slowly change round, so melons are low and lemons are high.
Hope this helped.
Improved Answer:-
If they are simultaneous equations then the lines will intercept af a point on the graph
The graph must have at least one intercept.
10
1) You write the equation in slope-intercept form, if it isn't in that form already. 2) An easy way to graph it is to start with the y-intercept. For example, if the intercept is +5, you graph the point (0, 5). Then you add an additional point, according to the slope. For example, if the slope is 1/2, you go 2 units to the right, and one up, and graph a point there.
If that should be y = 2 the slope is 0 and the y intercept is 2.
this is not a valid equation. I assume you mean: 2X+8Y=36 in which case the graph is a line with a slope of 1/4 and a y-intercept at 9/2 or 2X+4Y+2=36 in which case the graph is still a line with a slope of 1/2 and a y-intercept at 17/2
The graph must have at least one intercept.
10
1) You write the equation in slope-intercept form, if it isn't in that form already. 2) An easy way to graph it is to start with the y-intercept. For example, if the intercept is +5, you graph the point (0, 5). Then you add an additional point, according to the slope. For example, if the slope is 1/2, you go 2 units to the right, and one up, and graph a point there.
1
If that should be y = 2 the slope is 0 and the y intercept is 2.
1.5
you put the y intercept at 2, the x intercept at -2/3 and you join those two points.
1
If: x-y = -2 then the x intercept is -2 and the y intercept is 2 So the points are: (-2, 0) and (0, 2)
this is not a valid equation. I assume you mean: 2X+8Y=36 in which case the graph is a line with a slope of 1/4 and a y-intercept at 9/2 or 2X+4Y+2=36 in which case the graph is still a line with a slope of 1/2 and a y-intercept at 17/2
First write it in the "slope-intercept" form : y = mx + c Then the y-intercept is (0, c)
The graph is a line. One say is to put it in slope intercept form. Then you have the y intercept and the slope. You can graph the y intercept then use the slope to find the next point.So here goes:-5y=-2x+10so y=2/5x-2The y intercept it -2 and the slope if 2/5 .Plot the point (-2,0) and then go up 2 and over 5 to the right.Now do that again and it is easy to connect the 3 dots and draw the lines.You can also find the x intercept by letting y=0So you have 0=2/5x-2or 2/5x=2 so x=2(5/2)=5So the point (5,0) is the x intercept.