ONE WORD...FOIL. The FOIL method is a way to multiply binomials. "FOIL" is an acronym to remember a set of rules to perform this multiplication. To FOIL you multiply together all of the following: * F: Firsts * O: Outers * I: Inners * L: Lasts and then you add each of these products as demonstrated in the examples below. Let's take two arbitrary binomials. (x+a)(x+b) First: x^2 Outers: bx Inners: ax Last: ab So the product of these two binomials is x^2+bx+ax+ab Which we can simplify as x^2+x(a+b)+ab This is NOT the only way, another way is as below: (x+a)(x+b) Start with the x in x+a and multiply it by both terms in x+b so we have x^2+xb Now do the same with the a in x+a and we have ax+ab Add these all together and you have the same result as you did with the foil method. So why not just use foil? Why have two methods when one is plenty? GOOD QUESTION! The second method can be generalized to trinomials or any other types of polynomial multiplication and the FOIL method can't be.
To find the factor of 2 binomials
You use it in math, especially in algebra 1. The F.O.I.L method is like the distributive property basically.
They draw lines such as when you would try to figure out 7x6 you would make | for the 7 and _____ this way for the 6 then make half like circles on all 4 corners and count as you write them down. The answer is write every time but you can only do up to 2 digits.
use pemdas first...
when you multiply it with another polynomial
ONE WORD...FOIL. The FOIL method is a way to multiply binomials. "FOIL" is an acronym to remember a set of rules to perform this multiplication. To FOIL you multiply together all of the following: * F: Firsts * O: Outers * I: Inners * L: Lasts and then you add each of these products as demonstrated in the examples below. Let's take two arbitrary binomials. (x+a)(x+b) First: x^2 Outers: bx Inners: ax Last: ab So the product of these two binomials is x^2+bx+ax+ab Which we can simplify as x^2+x(a+b)+ab This is NOT the only way, another way is as below: (x+a)(x+b) Start with the x in x+a and multiply it by both terms in x+b so we have x^2+xb Now do the same with the a in x+a and we have ax+ab Add these all together and you have the same result as you did with the foil method. So why not just use foil? Why have two methods when one is plenty? GOOD QUESTION! The second method can be generalized to trinomials or any other types of polynomial multiplication and the FOIL method can't be.
To find the factor of 2 binomials
You use it in math, especially in algebra 1. The F.O.I.L method is like the distributive property basically.
you simply just use the FOIL method.:)
I think something's missing, but the answer is x(6x - 13)
No. His asst. John La Forge was the first one to use this method.
You use the FOIL method. First terms Outer terms Inner terms Last terms.
In the general case, this is quite tricky. In high school, you learn some simple cases. If the polynomial is of degree 2, you can use the quadratic function. For higher degrees, in some specific cases you can use the methods taught in high school to factor the polynomial. As you might know, once the polynomial is completely factored, it is quite trivial to find the zeros. But in the general case, you need some iterative method, which is more appropriate for a computer. From Wikipedia, article "Polynomial": "Numerical approximations of roots of polynomial equations in one unknown is easily done on a computer by the Jenkins-Traub method, Laguerre's method, Durand-Kerner method or by some other root-finding algorithm." You can read about any of these methods for more information; but don't expect a formula where you just "plug in some numbers"; rather, those are iterative methods, that is, you need to repeat a certain calculation over and over until you get a root of a polynomial with the desired accuracy.
They draw lines such as when you would try to figure out 7x6 you would make | for the 7 and _____ this way for the 6 then make half like circles on all 4 corners and count as you write them down. The answer is write every time but you can only do up to 2 digits.
The answer to a multiplication question is called the "Product".
They don't use the term, but they do use the device. Mercutio is a foil to Romeo in 1,4 and Benvolio is a foil to Mercutio in 3,1.