5x + 4 = 10x - 5 10x - 5x = 4 + 5 5x = 9 x = 1.8
6-3x = 5x-10x+2 4 = 8x-10x 4 = -2x x = -2
10x - 18 = 5x + 2 Add -5x + 18 to both sides of the equation, to get: 5x = 20, from which x = 4.
10x + 2y + 8z - 5x + 4z - 4y = 10x - 5x + 2y - 4y + 8z + 4z = (10 - 5)x + (2 - 4)y + (8 + 4)z = 5x - 2y + 12z
(3x)^(2-4) = (3x)^-2 = (9x2)^-1 = 1/(9x2)
5x + 4 = 10x - 5 10x - 5x = 4 + 5 5x = 9 x = 1.8
6-3x = 5x-10x+2 4 = 8x-10x 4 = -2x x = -2
10x - 18 = 5x + 2 Add -5x + 18 to both sides of the equation, to get: 5x = 20, from which x = 4.
It is: 10x^2 -4x = 2x(5x-2)
10x + 2y + 8z - 5x + 4z - 4y = 10x - 5x + 2y - 4y + 8z + 4z = (10 - 5)x + (2 - 4)y + (8 + 4)z = 5x - 2y + 12z
10x + 4/8
6-3x = 5x-10x+10 6-3x = -5x+10 -3x+5x = 10-6 2x = 4 x = 2
Well, you can factor this. (10X^2 + 5X)/5x 5X(2X + 1)/5X cancel 5X; top and bottom 2X + 1 set to 0 and see 2X+ 1 = 0 2X = - 1 X = -1/2 -----------check to see what we get [10(- 1/2)^2 + 5(- 1/2)/5(- 1/2) 10/4 - 5/2/- 5/2 5/2 - 5/2/- 5/2 = 0 ----------- I think so because my TI-84 agrees with this answer
(3x)^(2-4) = (3x)^-2 = (9x2)^-1 = 1/(9x2)
(5x - 2)(25x^2 + 10x + 4)
(5x - 2)(25x2 + 10x + 4)
5x/x-2