The square root of 7 is an irrational number. This means that there are no integer numbers a and b so that a/b=sqrt(7)
The square root of 49 is 7, which is a whole number. Specifically, it is a positive integer, as the square root of a positive number is defined to be the principal (non-negative) root. Additionally, 7 is also classified as a rational number because it can be expressed as a fraction (7/1).
Irrational
no, 28 has no whole square root; the square root of 49 is 7
irrational
JACK
The square root of 49 is 7, which is a whole number. Specifically, it is a positive integer, as the square root of a positive number is defined to be the principal (non-negative) root. Additionally, 7 is also classified as a rational number because it can be expressed as a fraction (7/1).
No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106
Seven.
Irrational
2
Square root of 2 = 1.414213562... Square root of 7 = 2.645751311... The sum is 4.059964873...
no, 28 has no whole square root; the square root of 49 is 7
the 4th root of 49 is the square root of the square root of 49 since square root 49 =7 then simplify is square root of 7
The square root of 49 is 7.7 times 7 is 49, so the square root of 49 is 7. 7
yes. Examples: the square root of 7 times the square root of 7 = 7 the square root of 7 times one over the square root of 7 = 1
The square root of 49 is 7, because 7 x 7 = 49
irrational