0
This does not quite work if you define sin(x) in terms of the ratio of the opposite side and the hypotenuse of a right angled triangle because you cannot have a triangle in which one of the angle measures 0 degrees.
One approach is to consider the limiting value of sin(x) as x approaches 0 from below and from above. But you would have to first prove (or assume) that sine is a continuous function at 0.
Another way is to consider sin(x) as the sum of the infinite series
sin(x) = x/1! - x3/3! + x5/5! - ... (where x is measured in radians).
This is the Taylor series definition of the sine function.
Clearly, every term is 0 when x = 0 and so you have sin(0) = 0
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How do you evaluate this limit Algebraically limit as x approaches 0 of 3sinx divided by x-2tanx without using Lhospital rule?
sinx = sin0 = 0 tanx = tan0 = 0 you have 0/0 by you limit conditions
What is the place value of 0 in the tens place?
Place value 0 in tens place is always 0 because 0 has no value.
What is the value of the first 0 in 30409?
Its value is 0, but its place value is ten thousands.
What is the place value of 0 in 2607?
The place value of 0 in 2607 is 0. In this number, 0 represents no additional value in the thousands place.
What does it mean by numeric value?
Numerical value = absolute value For any real number a, the absolute value of a, denoted by |a| is itself if a ≥ 0, and -a if a < 0. Thus |a| is positive expect when a = 0.
