There is no set length or width. It could be 1 foot wide and 525 feet long, or 22.91 ft by 22.91 ft.
Wiki User
∙ 6y agoTo determine the width and length of a space that is 525 square feet, you need additional information. The space can have various dimensions depending on its shape. For example, if it is a square, both the width and length would be approximately 23 feet. However, if it is a rectangle, the dimensions could be any combination that multiplies to 525.
Area = Length * Width So Length = Area / Width Length = 132/1q = 132/q feet
area = length x width width = area/length 16/8 = 2 feet
The width is 24 feet.
length of diagonal of 20 of a 20 feet and 15 width.
Area = Length * Width so Width = Area / Length = 72 sq feet / 12 feet = 72/12 feet = 6 feet.
Length in feet x width in feet = square feet.
1.091393 feet, if it's a cube.
The Space Shuttle cargo bay's dimensions are approximately 60 feet in length and 15 feet in width.
Exactly 40 cubic feet of it.Picture a cardboard box that is cubical . . . the length, width, and height are all the same.The box encloses 40 cubic feet of space if its length, width, and height are each [ 3feet 5.1inches ].
122ft Long, 78ft wide.
You don't measure the length and width in square feet. Square feet is an area. You measure the length and width in feet, then multiply them to get the area in square feet.
If the perimeter is 84 feet and the length is twice the width, then the length will be 28 feet and the width will be 14 feet.
Area = Length * Width So Length = Area / Width Length = 132/1q = 132/q feet
area = length x width width = area/length 16/8 = 2 feet
It all depends on the actual size of the space. Square footage is measured by multiplying the length of the space by the width. IE: a 6x6 space is 36sq feet.
The length is 7 feet and the width is 5 feet
The width is 6 feet. The length is 8 feet.