length of diagonal of 20 of a 20 feet and 15 width.
25 feet Pythagorean theorem says length of diagonal is square root of (width squared plus length squared). This is a 3-4-5 ratio right triangle
The diagonal is about 28.3 feet.
Perimeter = 2*(Length + Width) = 2*(15+9) = 48 feet.
The area of a rectangle is length x width.
An old train engine is 45 feet in Length, 7 feet in width and reaches 15 feet in height.
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
25 feet Pythagorean theorem says length of diagonal is square root of (width squared plus length squared). This is a 3-4-5 ratio right triangle
The diagonal is about 28.3 feet.
Perimeter = 2*(Length + Width) = 2*(15+9) = 48 feet.
The area of a rectangle is length x width.
Use Pythagoras: diagonal² = length² + width² → diagonal² = (10 cm)² + (15 cm)² → diagonal = √(10² + 15²) cm = √325 cm = 5 √13 cm ≈ 18 cm
An old train engine is 45 feet in Length, 7 feet in width and reaches 15 feet in height.
The area of a rectangle is the length times the width. In this case, 15' x 9' = 135 ft2.
The length is 20 cm.
Area = length x width, so the area of this rectangle would be 15 feet x 9 feet which equals 135 square feet.
If the width is x then the length is x+15 and the perimeter is x+x+x+15+x+15 (length + length + width + width). So: x + x + x + 15 + x + 15 = 210 4x + 30 = 210 {group x's} 4x = 180 {take 30 from each side} x = 45 {divide by 4} The width is 45 feet.
You would multiply the length with the width so 5 feet can be the width and 3 feet can be the length. 5x3=15 s/f