My foot
If your foot is twelve inches long then yes it is. The word foot was used to establish the measurement "a foot" because it is the approximate size of a mans foot.
A half of one foot is six inches long.
Since one foot is 12 inches a four percent slope is .04X12 = 0.48 inch drop
Drop per foot doesn't care about length of run, it depends on pipe size. Pipe larger than 2" needs only 1/8" per foot (37.5" fall for 300'), 2" and smaller needs 1/4" per foot (75" fall for 300')
I think it would last just for a day.
I had a herniated disc in the L5 S1 region that burst and fragmented...surgery went well but I am left with drop foot...will I regain full use of my foot...if so, how long will it take?
To calculate a quarter-inch drop per foot, you would divide 0.25 inches by 12 inches (since there are 12 inches in a foot). This would give you a drop of approximately 0.02083 inches per inch (or approximately 2.083%).
Foot drop often affect the muscles which are responsible for the ankle movement. Some typical symptoms of having a drop foot are limp foot, numbness, difficulty with certain activities and tingling.
Foot orthotics are not typically worn 24 hours a day to treat foot drop. They are usually worn during weight-bearing activities to provide support and alignment for the foot and ankle. Other treatment options for foot drop may include physical therapy, bracing, and sometimes surgery depending on the underlying cause.
The drop on Fahrenheit at Hersheypark lasts about 15 seconds from the moment the coaster begins descending until it levels out.
The whole ride takes about 44 seconds. The drop problably last for a bout 3-5 seconds.
its hold
Take a block of frozen water (ice) and drop it on your foot - ouch!. Then drop the same amount as water on your foot. I know I would prefer to drop water on my foot that solid ice.
Mantis has a top speed of 60 mph. It has a 137 foot drop and last 2 minutes and 40 seconds.
1 foot
Voltage drop is caused by resistance. From the equation V=IR the voltage across that resistance can be calculated. For a uniform conductor the resistance is linear with the length R=kx where k is in ohms per foot. For a given current, the voltage drop V=Ikx so the voltage drop per foot is Ik. Voltage drop per foot can be measured, allowing a calculation of voltage drop for very long lengths of conductor such as power transmission lines. This is a reasonable approximation as long as the total voltage drop in transmission is small relative to the supply voltage. If the voltage drop is large, the current will be limited by the total resistance. This implies that long distance transmission lines should be high voltage, because 1 megawatt at 10,000 volts requires 100 amps, while at 100,000 volts it only requires 10 amps. The voltage drop per foot for the same conductor would be 10 times as large at 10 times the current, and the power loss (I*IR) would be 100 times as large. For alternating current, inductance can be a factor; this implies that relatively low frequency would be preferred.