How long does it take for an average 6 foot tall man to fall 10 feet?

Answer 1

The time it takes for an object to fall can be calculated using the formula for free fall: ( t = \sqrt{\frac{2d}{g}} ), where ( d ) is the distance fallen and ( g ) is the acceleration due to gravity (approximately 32.2 feet per second squared). For a 10-foot fall, this results in ( t \approx \sqrt{\frac{2 \times 10}{32.2}} ), which is roughly 0.79 seconds. Thus, an average 6-foot tall man would take about 0.79 seconds to fall 10 feet.