Wiki User
ā 14y agodepends on weight of object and wind strength.
normally heavy objects will drop down faster than lighter objects.
Wiki User
ā 14y agoH = 1/2 G T2 = 1/2 (32.2) (1.5)2 = 36.23 feet
Acceleration of gravity near the surface of the earth is 9.8 meters (32.2 feet) per second2. Downward velocity after 2 seconds = 19.2 meters (64.4 feet) per second.
At the end of 3 seconds, a falling object is falling at 65.8 mph faster than when it was released, ignoring air resistance.
The mass is irrelevant. If the object is in free fall (that is, air resistance can be neglected), an object will fall 4.9 meters in one second.
Ignoring air resistance, the velocity of any object that goes off a cliff is 29.4 meters (96.5 feet) per second downward, after 3 seconds in free-fall.
The final velocity of an object in free-fall after 2.6 seconds is approximately 25.48 m/s. The distance the object will fall during this time is approximately 33 meters.
Assuming that air resistance can be ignored, the answer is yes.
4 Seconds
The time it takes for an object to fall a certain distance in a vacuum can be calculated using the equation for free fall: time = sqrt(2 * distance / gravity). Plugging in the values, it would take approximately 4.74 seconds for an object to fall 176.4 meters in a vacuum since there is no air resistance.
Assuming the object starts from rest, the distance an object falls in 0.25 seconds can be calculated using the equation ( d = \frac{1}{2}gt^2 ), where (d) is the distance, (g) is the acceleration due to gravity (9.8 m/sĀ²), and (t) is the time. Substituting the values, the object would fall approximately 0.31 meters in 0.25 seconds.
Assuming the object is falling under gravity, it will fall approximately 78.4 meters in 4 seconds. This is based on the formula: distance = 0.5 x acceleration due to gravity x time squared.
An object in free fall will fall approximately 64 feet in 2 seconds.
The speed of an object in free fall after falling for 2 seconds is approximately 19.6 m/s.
In 4 seconds of free fall, an object would fall approximately 78.4 meters, assuming no air resistance. This calculation is based on the acceleration due to gravity being approximately 9.81 m/s^2.
Assuming the object is in free fall near Earth's surface, it will fall approximately 343.3 meters (1126 feet) in 7 seconds. This calculation is based on the formula for free fall distance: d = 1/2 * g * t^2, where d is the distance fallen, g is the acceleration due to gravity, and t is the time in seconds.
The instantaneous speed equation is v = at, where a is 9.81 meters per second squared. The instantaneous speed is then 78.48 meters per second. The distance is equal to d = 1/2 a t t. The distance is then 313.92 meters.
On object falling under the force of gravity (9.8 m/s2) would, in a vacuum, fall a distance of 706 metres in 12 seconds. In a non-vacuum, i.e. air, the object would fall less distance in the same time due to drag.xt = 0.5 (9.8) t2