If the paper is in inches then 11 times 14 = 154 square inches
Many people will say half double the length or two times the distance from the midpoint to the end but the truth is that the average piece of string is 14 feet long.
Let p be the size of the smallest piece. Then we know that it (p) plus the middle piece (p + 5) and the longest piece (3 x p) adds up to 75. p + (p+5) + 3p = 75 => 2p + 5 + 3p = 75 => 5p = 75 - 5 => 5p = 70 => p = 14 So the smallest piece is p = 14 ft. The middle piece is p + 5 = 19 ft. And the largeset peice is 3p = 42 ft. Adding the sizes to check: 14 + 19 + 42 = 75
Perimeter = width*2 + length *2 112 = 14 * 2 + length * 2 56 = 14 + length length = 56 - 14= 42
To find the area of a square, you square the length of one side. In this case, if the side length is 14 meters, you would calculate 14 meters x 14 meters = 196 square meters. So, 14 meters is equivalent to 196 square meters in terms of area.
If 104 yards of ribbon is cut into 14 equal length pieces, each piece will have length of 7.43 yards, to the justified number of significant digits.
3 shelves and a 6 inch piece left over.
If the paper is in inches then 11 times 14 = 154 square inches
Correct me if I am wrong but I think the answer is One piece will measure 22 inches The other should measure 14 inches As 2 x 14 = 28 therefore 22 inches is six inches less than 28
Many people will say half double the length or two times the distance from the midpoint to the end but the truth is that the average piece of string is 14 feet long.
6 inches.
Let p be the size of the smallest piece. Then we know that it (p) plus the middle piece (p + 5) and the longest piece (3 x p) adds up to 75. p + (p+5) + 3p = 75 => 2p + 5 + 3p = 75 => 5p = 75 - 5 => 5p = 70 => p = 14 So the smallest piece is p = 14 ft. The middle piece is p + 5 = 19 ft. And the largeset peice is 3p = 42 ft. Adding the sizes to check: 14 + 19 + 42 = 75
It is 11 inches by 14 inches. It is wider than a regular piece of paper but the same length.
oasis was cut into 14 parts by his brother set {seth}
It will fit 19 pictures in the height, and 14 pictures in the length of the frame. This gives us 19*14=266 pictures. Unless you want to cut your pictures, this is the correct solution.
14
Perimeter = width*2 + length *2 112 = 14 * 2 + length * 2 56 = 14 + length length = 56 - 14= 42