1 foot = 12 inches
16 inches = 1foot 4inches = 4/3 foot
16" x 16" = 4/3 x 4/3 = 16/9 square feet per tile
900 square feet/16/9 = 900 x 9/16 = 5061/4 tiles.
You should probably buy 507 of them.
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12 " x 12 " = 1 foot by 1 foot = 1 sq foot. 900 / 1 = 900 tiles are needed (plus waste).
A 900 sq foot area will have a 30 ft side (Sqrt(900)=30) So given that 16 inches = 1.333 feet # tiles on edge = 30/1.333 = 22.5 22.5^2 = 507 tiles
18 inch x 18 inch tile is really (1 and 1/2) feet by (1 and 1/2) feet That is (3/2) x(3/2) square feet = 9/4 square feet. To cover 900 square feet we need (900)/(9/4) = (900) x (4/9) = 100 x 4 = 400 tiles
20 inches = 20/12 ft = 1.67ft6 inches = 6/12 ft = 0.5ft1.67X0.5 ft = 0.83 sq ft.Therefore 900sq ft / 0.83 sq ft = 1080 tilesHowever the above answer is how much is needed without waste. I.e. no partial tiles for the perimeter.
18"x18"/144 sq inches per sq ft = 2.25 sq ft per tile for 18x18 tiles 900 sq ft / 2.25 sqft/tile = 400 tiles +10% for waste and cuts = 440 tiles