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How many even 3-digit numbers can be formed from digits 0 1 2 4 5 7 9 if each digit can be used only once?
To solve this question, two cases must be considered:Case 1: The three-digit even number ends with 0.If the three-digit number ends with 0, then the number must be even. After the digit 0 is used, six digits remain. After any one of these six digits is chosen to be the first digit, five digits remain. To complete the number, any of the five remaining digits could be chosen to be the second digit of the number.___6___ * ___5___ * ___1___ = 30 three-digit even numbers ending in 0.1st digit-------2nd digit----3rddigit (0)Case 2: The three-digit even number does not end with 0.If the three-digit number does not end with 0, it can end with 2 or 4. Therefore, there are two possibilities for the third digit. The first digit could be any of the remaining digits, EXCEPT 0: if 0 were the first digit, it would not be a three-digit number. Therefore, there would be five possible digits for the first digit. 0 could be used as the second digit, along with the four remaining digits that were not previously used.___5___ * ___5___ * ___2___ = 50 three-digit even numbers not ending in 0.1st digit-------2nd digit-----3rddigit (0)The total number of three-digit even numbers is 80, since 30 three-digit even numbers ending in 0 plus 50 three-digit even numbers not ending in 0 equals 80.
Is 0 a digit or a number?
0 is a digit
Why can a prime number not have 0 as its digit?
Everything that has 0 as its digit can be divided by both 2, and 5 as well as many more. Therefore it cannot be a prime number.
How do you divide two digit by three digit numbers?
I think that you would just add a .0 to the end of the two digit number, thus making it three digit, then divide. At the end, you have to put the decimal on the answer in the right place, though.
Why is 90 divisible by 10?
90 is divisible by 10 because it has a 0 as its end digit. Any number with a zero as the end digit gives an integer result when dividing by 10.
How many even 3-digit numbers can be formed from digits 0 1 2 4 5 7 9 if each digit can be used only once?
To solve this question, two cases must be considered:Case 1: The three-digit even number ends with 0.If the three-digit number ends with 0, then the number must be even. After the digit 0 is used, six digits remain. After any one of these six digits is chosen to be the first digit, five digits remain. To complete the number, any of the five remaining digits could be chosen to be the second digit of the number.___6___ * ___5___ * ___1___ = 30 three-digit even numbers ending in 0.1st digit-------2nd digit----3rddigit (0)Case 2: The three-digit even number does not end with 0.If the three-digit number does not end with 0, it can end with 2 or 4. Therefore, there are two possibilities for the third digit. The first digit could be any of the remaining digits, EXCEPT 0: if 0 were the first digit, it would not be a three-digit number. Therefore, there would be five possible digits for the first digit. 0 could be used as the second digit, along with the four remaining digits that were not previously used.___5___ * ___5___ * ___2___ = 50 three-digit even numbers not ending in 0.1st digit-------2nd digit-----3rddigit (0)The total number of three-digit even numbers is 80, since 30 three-digit even numbers ending in 0 plus 50 three-digit even numbers not ending in 0 equals 80.
How many 2-digit numbers end in 0?
There are 9 of them.
Is 0 a digit or a number?
0 is a digit
How do you write a visual basic program to sum the odd number digits of a 12 digit code using division and Mod and while loops?
Function sum_odd_digits(ByVal number As Integer) As Integer Dim digit As Integer sum_odd_digits = 0 While number <> 0 digit = number Mod 10 If digit And 1 Then sum_odd_digits = sum_odd_digits + digit number = number / 10 End While End Function
When a number is a multiple 5 what are the possible values for the ones digit?
Its multiples will have 5 or 0 at the end of the number.
Why can a prime number not have 0 as its digit?
Everything that has 0 as its digit can be divided by both 2, and 5 as well as many more. Therefore it cannot be a prime number.
How do you divide two digit by three digit numbers?
I think that you would just add a .0 to the end of the two digit number, thus making it three digit, then divide. At the end, you have to put the decimal on the answer in the right place, though.
Why is 90 divisible by 10?
90 is divisible by 10 because it has a 0 as its end digit. Any number with a zero as the end digit gives an integer result when dividing by 10.
Name a 10 digit Number such that the first digit on the left tells how many 0 are in the numbers?
1234567890
What digit do you put at the end of a number when you multiply it by ten?
Any integra number timed bt ten would be exacly adding a zero (0) to the end of the number. ^^
How many 2's whole numbers between 0 and 99 contain the digit?
greatest two digit number is 99. smallest whole number is 0 there fore 99-0=99
How do you multiply a 2-digit number by a 2-digit number?
0
