You would need four buses. Three would be full and there would be six people on the last bus.
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Different double-decker buses can carry different numbers of passengers. If all the passengers were to be seated, you would need 13889 London red buses. Of course, a single double-decker bus, over its lifetime, will carry a million (or more) passengers.
One EasyJet Plane (Airbus A319) can carry about 124 passengers. So, 20,161 such planes would be needed for 2.5 million passengers.
If the probability that a bus arrives on time 4 sevenths of a time, it means that for every 7 buses, 4 arrive on time. By deduction it also means that for every 7 buses 3 of them come late. If out of 7 buses 3 come late can you figure out how many buses out of 210 buses will be late based on the same probability? I am sure you can. Good luck!
That would depend on the specification. For example, in a war you're not going to want a Boeing 787, you want a fighter plane (e.g the lockheed martin f35 raptor II) but the opposite would be the case in an airline where you need to carry passengers efficiently which is where the Boeing 787 excels but the F35 raptor fails.
Coins were created to make it possible to get things without trading for them. Before people had money, they would trade, for example a basket of beans for a goat, but you don't always want to carry around beans or goats, so people invented money.