The first digit can be any one of the 9. For each of these . . .
The second digit can be any one of the 8 not already used. For each of these . . .
The third digit can be any one of the 7 not already used.
Total number of possibilities = (9 x 8 x 7) = 504
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500
180 of them.
It is 120 if the digits cannot be repeated.
There are 34 = 81 numbers.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24