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9*8*7 = 504 of them.

Q: How many 3 digit numbers can be formed using the digits 1 to 9 without repetition?

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15 of them.

I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24

Six (6)

3*2*1 = 6 of them.

64 if repetition is allowed.24 if repetition is not allowed.

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15 of them.

I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24

There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.

Six (6)

3*2*1 = 6 of them.

64 if repetition is allowed.24 if repetition is not allowed.

1

# 230 # 203 # 320 # 302

If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.

There are 4*4*3*2*1 = 96 such numbers.

125

None :) You only gave us 4 numbers!