Best Answer

Ans is: 180

units place can filled in 2 ways

tens place can filled in 10 ways

hundreds place can filled in 9 ways

=2*10*9=180

Q: How many 3 digit numbers can be formed which are divisible by 5 using the digits 0 1 2 3 4 5 6 7 8 9 if repetitions of digits are allowed?

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pizza

There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.

Assuming all 45 digits are different (which they will not be if they are ordinary integers), then 456, if repetitions are allowed. That is 8303765625. If repetitions are not allowed then the number falls to 45*44*43*42*41*40 = 5864443200

If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.

numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4

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pizza

There are 5 numbers of 1 digit, 25 numbers of 2 digits, and 75 numbers of 3 digits. This makes 105 numbers in all.

24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.

Assuming all 45 digits are different (which they will not be if they are ordinary integers), then 456, if repetitions are allowed. That is 8303765625. If repetitions are not allowed then the number falls to 45*44*43*42*41*40 = 5864443200

2,401

If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.

10,000

5^4

No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9

All numbers that are divisible by 6 are even numbers whose digits add up to 3 or a multiple of 3. Example : 284 is not wholly divisible by 6 as although it is even, its digits total 2 + 8 + 4 = 14 which is not divisible by 3. 282 is divisible by 6 as it is even and its digits total 12 which is divisible by 3.

numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4

All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.