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To form a three-digit number using the digits 0-9, the first digit cannot be 0 (as it would not be a three-digit number). Thus, the first digit can be any of the digits from 1 to 9 (9 options). The second and third digits can each be any digit from 0 to 9 (10 options each). Therefore, the total number of three-digit numbers is (9 \times 10 \times 10 = 900).
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How many 3 digit numbers divisible by 9 can be formed from the digits 0123456789?
There are 76 such numbers. Eight more if you allow numbers to start with 0.
How many four digit numbers can be made from 1123?
There are 12 such numbers.
How many 3 digit numbers can be prepaired with no number repeated with the numbers 0123456789?
-- The first digit can be any one of nine. (It can't be zero).-- The second digit can be any one of nine. (Anything except the one you used for the first digit.)-- The third digit can be any one of eight. (Anything except the two already used.)Total possibilities = (9 x 9 x 8) = 648
How many 4 digit numbers are all made of prime numbers?
24 of them.
How many sets of 3-digit numbers can be made using 7 numbers and no duplicates within the 3-digit number?
210
