There are 76 such numbers. Eight more if you allow numbers to start with 0.
There are 12 such numbers.
-- The first digit can be any one of nine. (It can't be zero).-- The second digit can be any one of nine. (Anything except the one you used for the first digit.)-- The third digit can be any one of eight. (Anything except the two already used.)Total possibilities = (9 x 9 x 8) = 648
24 of them.
210
There are 76 such numbers. Eight more if you allow numbers to start with 0.
Assuming that numbers with a leading zero is not permitted, the answer is 9*9! = 3,265,920. If leading 0s were permitted, the answer would have been 3,628,800
id say, 0123456789. but depends how many digits you can have
-123456786
The number of six digit numbers that you can make from ten different digits ifrepetitions of same digit on the six digit number is allowed is 1 000 000 numbers(including number 000 000).If no repetitions of the the same digit are allowed then you have:10P6 = 10!/(10-6)! = 151 200 different six digit numbers(six digit permutations form 10 different digits).
There are 12 such numbers.
999-111=888 888 3 digit numbers can be made with numbers between 1 - 9
-- The first digit can be any one of nine. (It can't be zero).-- The second digit can be any one of nine. (Anything except the one you used for the first digit.)-- The third digit can be any one of eight. (Anything except the two already used.)Total possibilities = (9 x 9 x 8) = 648
a lot
24 of them.
90000
2