To form a three-digit number using the digits 0-9, the first digit cannot be 0 (as it would not be a three-digit number). Thus, the first digit can be any of the digits from 1 to 9 (9 options). The second and third digits can each be any digit from 0 to 9 (10 options each). Therefore, the total number of three-digit numbers is (9 \times 10 \times 10 = 900).
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There are 76 such numbers. Eight more if you allow numbers to start with 0.
There are 12 such numbers.
-- The first digit can be any one of nine. (It can't be zero).-- The second digit can be any one of nine. (Anything except the one you used for the first digit.)-- The third digit can be any one of eight. (Anything except the two already used.)Total possibilities = (9 x 9 x 8) = 648
24 of them.
210