There are 12 such numbers.
Wiki User
∙ 9y agoThere are 24.
3*3*2*1 = 18
I assume you mean how many 4-digit numbers can be made from a set such as {A,A, B, C} where A, B and C are single digits. There are 12 such numbers.
2 Nope! definitely not 2.. The answer should be 126 I'm looking for the solution. Eg. Q. How many 4 digit numbers can be made from the digits 1-9 A. 9X8X7X6= 3024.
-4
There are 24.
3*3*2*1 = 18
I assume you mean how many 4-digit numbers can be made from a set such as {A,A, B, C} where A, B and C are single digits. There are 12 such numbers.
2 Nope! definitely not 2.. The answer should be 126 I'm looking for the solution. Eg. Q. How many 4 digit numbers can be made from the digits 1-9 A. 9X8X7X6= 3024.
It is a permutation problem (any number can be used repeatedly), it will become 4 x 4 x 4 x 4 = 256 four digit numbers. If each number can only be used once, then the answer is 4 x 3 x 2 x 1 = 24 four digit numbers.
-4
Allowing numbers that start with zero, the answer is 6!/(2!*2!) = 720/(2*2) = 180
The first digit can by selectd in one of two ways, since a number starting with zero would not be a 5-digit number. After that, each of the other four digits can be selected in 3 ways. So the number of 5-digit numbers is 2*34 = 162
999-111=888 888 3 digit numbers can be made with numbers between 1 - 9
If you're asking for 4 digit numbers where all four digits are odd, then the lowest number possible is 1111, and the highest is 9999. You only have 5 digits to work with. The answer is: 54 - 53 = 625 - 125 = 500.Subtract the 5 cubed for the numbers less than 1111, which are not four digits.
You can select 12 numbers for the first digit, 11 numbers for the second digit, and 10 numbers for the third digit; so 12*11*10 = 1320 sets of 3 numbers can be made out of 12 different numbers.
If the digits may be repeated, there are four choices for the first digit, four choices for the second, and four choices for the third. Thus there are 4x4x4 = 64 possible three-digit numbers with those digits. If the digits may not be repeated, there are still four choices for the first digit, but then only three remaining choices for the second, and then just two choices for the third. In this case there are only 4x3x2 = 24 possibilities.