Using the combination C(4,3) I got the answer 24. Its either a combination or a permutation.
With 123 digits you can make 123 one-digit numbers.
24
3*3*2*1 = 18 of them.
6 2-digit numbers (13/15/35/53/51/31)
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
With 123 digits you can make 123 one-digit numbers.
9
You can make 4*4*4 = 64 numbers.
If you want 4-digit numbers, there are 24 of them.
600 of them.600 of them.600 of them.600 of them.
3*3*2*1 = 18 of them.
24
6 2-digit numbers (13/15/35/53/51/31)
Six, if you don't repeat any digits.
1983 derp derp derp
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.