Using the combination C(4,3) I got the answer 24. Its either a combination or a permutation.
With 123 digits you can make 123 one-digit numbers.
24
3*3*2*1 = 18 of them.
6 2-digit numbers (13/15/35/53/51/31)
The four-digit numbers that can be formed using the digits 6, 7, 8, and 9, without repetition, are all the permutations of these four digits. There are 24 possible combinations, including numbers like 6789, 6798, 6879, and so on. Essentially, any arrangement of these four digits constitutes a valid four-digit number.
With 123 digits you can make 123 one-digit numbers.
9
If you want 4-digit numbers, there are 24 of them.
24
3*3*2*1 = 18 of them.
600 of them.600 of them.600 of them.600 of them.
6 2-digit numbers (13/15/35/53/51/31)
Six, if you don't repeat any digits.
1983 derp derp derp
The four-digit numbers that can be formed using the digits 6, 7, 8, and 9, without repetition, are all the permutations of these four digits. There are 24 possible combinations, including numbers like 6789, 6798, 6879, and so on. Essentially, any arrangement of these four digits constitutes a valid four-digit number.
I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24
1,956 different numbers can be made from 6 digits. You can calculate this by using the permutation function in a summation function, like this: Σ6k=1 6Pk = 6P1+6P2+...+6P5+6P6 What this does is calculate how many 1 digit numbers you can make from 6 digits, then how many 2 digit numbers can be made from 6 digits and adds the amounts together, then calculates how many 3 digit numbers can be made and adds that on as well etc.