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How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?

If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.


How many 2-digit numbers can be formed using the digits 1 3 7 if repetition of digits is allowed?

Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77


How many 3 digit numbers can be formed from the digits 1234?

64 if repetition is allowed.24 if repetition is not allowed.


How many numbers can be formed using the digits 37 and 9 without repetition?

15 of them.


How many 4 digit numbers can be formed from digits 123456789?

5040 different 4 digit numbers can be formed with the digits 123456789. This is assuming that no digits are repeated with each combination.


How many 3 digits odd numbers can be formed from the digits 1 2 3 4 and 5 if repetition is not allowed?

125


How many three digit numbers can be formed using the digits 873 and 6 without repetition?

I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24


How many 3-digit numbers can be formed by the digits 4 5 9 without repetition?

Six (6)


How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?

There are 2000 such numbers.


How many odd numbers less than 100 can be formed by using the digits 0 3 5 7 when repetition fo digits is not allowed?

9 odd numbers less than 100 can be formed. They are: 3,5,7,35,37,53,57,73 and 75.


How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?

There are 2000 such numbers.


How many 3 digit numbers can be formed using the digits 1 to 9 without repetition?

9*8*7 = 504 of them.