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We put our cryptographers to work on this apparently coded question, and asked them
to decipher what it's trying to ask. They struggled and debated among themselves for
quite some time. Then, just before lunch, they agreed that there is an 83% probability
that the question is:
"How many 3-digit numbers can be made with the common decimal digits zero through 9 ?"
The largest one is 999, so there would be 999 of them, but the first 99 don't count, because
the numbers 1 - 99 have less than 3 digits.
So there are (999 - 99) = 900 different 3-digit numbers.
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How many arrangements of 3 digits can be formed from the digits 0 through 9?
1000
How many combinations of 3 digits of 0-9?
1000
How many permutations of 3 different digits are there from the ten digits 0 to 9 inc?
The answer is 10P3 = 10!/(10-3)! = 10*9*8 = 720
If you count from 1 to 100 how many 6's will there be?
you can image the 3 digits as a counter 0 0 1 0 0 2 ... ... ... 9 9 8 9 9 9 every digit uses 100 times a 6..... 100*3 digits = 300 sixes :)
How many 3 digit can you write using digits 0-9 without repeating?
648
