There are four different groups of three, each of which can be arranged in six different ways so your answer is 24.
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Assuming you can have duplicate letters such as AAA, AAB etc... there are 26 x 26 x 26 combinations - which is a total of 17,576 permutations !
233 = 18 combinations.
There are 3 consonants from 21 and 2 vowels from 5. That gives 21C3 * 5C2 combinations = 21*20*19/(3*2*1) *5*4/(2*1) = 1330*10 = 13300 combinations in all.
3 items each in 3 categories gives 3*3*3 = 27 possible combinations.