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18.You can answer it easily by considering three places for three digits of the number.The hundreds place cannot take zero hence it can take 2 values.The next two places can take all the three digits.Hence the total number of ways is 2*3*3=18.

Q: How many 3digit numbers can be formed from digits320 with repetition?

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There are 504 such numbers.

If repetition is allowed . . . . . 343 If repetition is not allowed . . . . . 210

64 if repetition is allowed.24 if repetition is not allowed.

15 of them.

There are 5*5*5 = 125 such numbers.

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There are 504 such numbers.

If repetition is allowed . . . . . 343 If repetition is not allowed . . . . . 210

64 if repetition is allowed.24 if repetition is not allowed.

15 of them.

There are 5*5*5 = 125 such numbers.

Six (6)

There are 600 such numbers.

There are 2000 such numbers.

I take it that you want to make three digits numbers with 8,7,3, and 6 without repetition. The first digit cane be selected from among 4 digits, the second from 3 digits, the third digit from 2, hence the number of three digit numbers that can be formed without repetition is 4 x 3 x 2 = 24

There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.

if the repetition is allowed the there is 6*6*6 possible ways = 216

9*8*7 = 504 of them.