There would be nine 3s with a remainder of two. 3 goes into 27 nine times, so the remaining two (29-27) are left over.
102 ÷ 3 = 34
32
15
142 divided by 3 equals 47 with a remainder of 1.
37.6666667
20
There would be nine 3s with a remainder of two. 3 goes into 27 nine times, so the remaining two (29-27) are left over.
There are 29 3s because there also a 3 in the how many 3s are in 83333333333333333333333333333
1,000 x 3 = 3,000
102 ÷ 3 = 34
32
15
75 ÷ 3 = 25
28 3s
It's in the tables of 1s, 3s, 9s, and 27s .
8 of them, with 2 left over.