Oh, dude, there are like four 3s in 12. It's simple math, just divide 12 by 3 and you get 4. Easy peasy lemon squeezy.
Bring all the unknown values to one side and the known values to the other 7s - 12 = 3s - 4 Subtract 3s from both sides 7s - 3s - 12 = 4 4s - 12 = 4 Add 12 to both sides 4s = 4 + 12 4s = 16 Divide both sides by 4 s = 4
12 1/3s is 12/312/3 = 4
To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
16
4
4 3s = 4*3 = 12, which is a rational number.
12
Bring all the unknown values to one side and the known values to the other 7s - 12 = 3s - 4 Subtract 3s from both sides 7s - 3s - 12 = 4 4s - 12 = 4 Add 12 to both sides 4s = 4 + 12 4s = 16 Divide both sides by 4 s = 4
To solve the equation 2s + s + 12 = 132, you first combine like terms on the left side. This gives you 3s + 12 = 132. Next, you isolate the variable by subtracting 12 from both sides to get 3s = 120. Finally, you divide by 3 on both sides to find that s = 40.
2s + s + 12 =132 ie 3s = 132 -12 3s = 120 s = 40
Magnesium (Mg) has an atomic number of 12, indicating it has 12 electrons. The electron configuration for magnesium is 1s² 2s² 2p⁶ 3s². Therefore, there are 2 electrons in the 3s subshell of magnesium.
28 3s
12 1/3s is 12/312/3 = 4
To find out how many 3s go into 140, divide 140 by 3. This gives you approximately 46.67. Since we're looking for whole 3s, you can fit 46 complete 3s into 140.
its clearly 8 3 6 9 12 15 18 21 4
In a magnesium atom, the valence electrons are located in the 3s sublevel. Magnesium has an atomic number of 12, which means it has 12 electrons. The electron configuration is 1s² 2s² 2p⁶ 3s², indicating that the two valence electrons reside in the 3s sublevel.
It is 1.08333... (with the 3s repeating).