If you can't repeat digits and the order of the digits matters,
you can make (9 x 8 x 7 x 6) = 3,024 patterns.
If you can't repeat digits and the order of the digits doesn't matter,
you can make (9 x 8 x 7 x 6)/(4 x 3 x 2 x 1) = 126 unique groups.
If you can repeat digits and the order of the digits matters,
you can make (9 x 9 x 9 x 9) = 6,561 patterns.
If you can repeat digits and the order of the digits doesn't matter,
you can make 273 unique groups.
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Precisely 1. For ANY number n, the number of combinations of n of those items is always 1.
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.
If it is 7 object out of 7, then just 1.
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
There are 56C5 = 56*55*54*53*51/(5*4*3*2*1) = 3,819,816 combinations.