55 of them.
55 is a bigger number than 5; 55 is in fact 11 5s.
55 + 5/5
One possibility is 55 + 5*5 = 55 + 25 = 80
Two if you're writing, eleven if you're dividing.
To write four 5s and make them represent 56 you need to write 55 + 5/5. When worked out it becomes 55 + 1 (5/5=1) which equals 56.
21 5s
(5 x 5) + (5 x 5) + 5 = 25 + 25 + 5 = 50 + 5 = 55
In the Rb atom, the electron configuration is [Kr]5s^1. This means there is 1 electron in the 5s sublevel of the Rb atom.
7
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