823543
There are 8*9*8*7*6*5*4 = 483840 numbers.
Using your rule - essentially, it's the simplified sum of 9999999-2000000 which is a total of 7999999 numbers !
7
The first digit can be formed in 8 ways (excluding 0 and 1). The rest of the 6 digits each can be filled in 10 ways. The total number of digits, therefore is 8 x 10^6.
Assuming all digits are equally likely, then it is 0.9395.However, that assumption is flawed since some numbers begin with 0. Some sequences are reserved and so on. So the distribution of numbers is NOT truly random and the above answer depends on all seven digit numbers being equally likely..
There are 8*9*8*7*6*5*4 = 483840 numbers.
Using your rule - essentially, it's the simplified sum of 9999999-2000000 which is a total of 7999999 numbers !
7
The first digit can be formed in 8 ways (excluding 0 and 1). The rest of the 6 digits each can be filled in 10 ways. The total number of digits, therefore is 8 x 10^6.
10 digit numbers
Without restrictions, it was would numbers 000-000-0000 through 999-999-9999. So that would be 9,999,999,999 + 1 = 10 billion different 10-digit phone numbers. Ex: If there existed single digit phone numbers, there would be 10, because the digits are 0 through 9. If there existed only double digit phone numbers, then it would be 00 through 99 which would be 100 total two-digit numbers. Therefore the total possible combinations for an X digit phone number would be: 10^X
A 4 digit pin is the last four numbers in your phone number.
Assuming all digits are equally likely, then it is 0.9395.However, that assumption is flawed since some numbers begin with 0. Some sequences are reserved and so on. So the distribution of numbers is NOT truly random and the above answer depends on all seven digit numbers being equally likely..
A 4 digit pin is the last four numbers in your phone number.
The first digit: 6
2020
No, my second to last phone number ended in 3836.