Oh, dude, let me break it down for you. So, since the first digit can't be 0 or 1, we have 8 options for that first digit. After that, we have 9 options for the next digit, then 8 for the next, and so on. So, it's like 8 x 9 x 8 x 7 x 6 x 5 x 4. Crunch those numbers and you get the total number of 7-digit phone numbers that can be formed without repeating any digits.
It is 120 if the digits cannot be repeated.
81
823543
jfnvjsdkncjfdknvlakdjvbsadoihfcb shfvbcnsHLfc bnshJCbvjhbeshuyvbe b hdfbgehfgbwahucgbvfer fguy gyfuby uyr
Using your rule - essentially, it's the simplified sum of 9999999-2000000 which is a total of 7999999 numbers !
1 set
It is 120 if the digits cannot be repeated.
81
823543
jfnvjsdkncjfdknvlakdjvbsadoihfcb shfvbcnsHLfc bnshJCbvjhbeshuyvbe b hdfbgehfgbwahucgbvfer fguy gyfuby uyr
Using your rule - essentially, it's the simplified sum of 9999999-2000000 which is a total of 7999999 numbers !
4*3*2*1 = 24
3x3x3=27
500
24
7
There are 5! = 120 such numbers.