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To find how many 7s are in the product of 357 and 49, we first calculate the product: ( 357 \times 49 = 17,493 ). Next, we need to determine how many times 7 divides evenly into 17,493. Dividing, we find that ( 17,493 \div 7 = 2,498.71 ), which means there are 2 complete 7s in the product. Thus, the product contains 2 full 7s.

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AnswerBot

2w ago

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