To find how many times the digit '9' appears between 1 and 1100, we can analyze each digit place (hundreds, tens, and units) separately. In the range from 1 to 999, the digit '9' appears 300 times: 100 times in the units place (from 9, 19, ..., 999), 100 times in the tens place (from 90-99, 190-199, ..., 990-999), and 100 times in the hundreds place (from 900-999). In the range from 1000 to 1100, '9' does not appear. Therefore, the total count of '9's from 1 to 1100 is 300.
Eleven.
111 of them with a remainder of 1
There are: 640/9 = 71 with a remainder of 1
9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92
1% of 1100 = 1% * 1100 = 0.01 * 1100 = 11
Eleven.
The answer between 1 and 1000 is 840, but what about 1 and 1100?
111 of them with a remainder of 1
There are: 640/9 = 71 with a remainder of 1
9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92
8, remainder 1
1% of 1100 = 1% * 1100 = 0.01 * 1100 = 11
1% of 1100 = 1% * 1100 = 0.01 * 1100 = 11
1 or 4 , depending on your point of view.
11 with 1 remaining 100 - 1 = 99 = 9 x 11
1 ns (nanosecond) = 10-9s 1s / 10-9s = 109 109 = 1000 000 000 1 second = 1000 000 000 ns (nanosecond)
there are 1000 metres in 1 kilometre therefore 1100 metres = 1.1 kilometre