11 with 1 remaining 100 - 1 = 99 = 9 x 11
111 of them with a remainder of 1
9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99 =20
Well there will be 1 nine for all the 9s in the units column (9, 19, 29 etc.), and 1 nine for all the numbers with 9 in the tens column (90, 91, 92 etc.). So the answer is 20.
There are: 640/9 = 71 with a remainder of 1
11 with 1 remaining 100 - 1 = 99 = 9 x 11
There are exactly 20 Nines. 9,19,29,39,49,59,69,79,89,90,91,92,93,94,95,96,97,98 which totals 18 and the last number 99 has 2 nines and therefore 20 nines in total.
111 of them with a remainder of 1
9^2+9+9 +9/9 81+9+9+1=100
9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99 =20
Well there will be 1 nine for all the 9s in the units column (9, 19, 29 etc.), and 1 nine for all the numbers with 9 in the tens column (90, 91, 92 etc.). So the answer is 20.
There are: 640/9 = 71 with a remainder of 1
9, 19, 29, 39, 49, 59, 69, 79, 89, 90, 91, 92
101
25 numbers are between 1-100.
100
8, remainder 1