9^2+9+9 +9/9 81+9+9+1=100
9÷9+99 or 99+9÷(9)
5
9 x 9 = 81 81 + 9 = 90 90 + 9/.9 = 90 + 10 = 100 i.e. (9 x 9) + 9 + 9/.9 = 100 ---- 99 + sin(99 - 9)o = 100
There are 5/100 = five hundredths or as 75/100 = seventy five hundredths
9^2+9+9 +9/9 81+9+9+1=100
It is five.
Eleven.
99 plus 9/9 = 100
20
(99)/(99) +9.
(9*9)+(9+9)+(9/9) = 100
11
Yes, there are an infinite number of posibilities. Staying only with positive odd numbers, if duplicates are allowed, then five 9s and five 11s make 100. If duplicates are disallowed, then 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 = 100
11 with 1 remaining 100 - 1 = 99 = 9 x 11
One way: 99 + 9/9 = 100
The GCF of 9s and 63s^3 is 9s.