To transform one pound of ice at 30°F into one pound of steam at 214°F, you need to consider several steps: melting the ice to water, heating the water to 212°F, converting the water to steam, and then heating the steam to 214°F. The total energy required can be calculated using specific heat values and latent heats. Roughly, this amounts to about 1,000 Btu for melting, 90 Btu for heating the water, 1,000 Btu for vaporization, and 2 Btu for heating the steam, totaling around 2,092 Btu.
This is the latent heat of vaporisation of water, which at standard pressure, is 539 calories (per gram).
6,520 Btus
Leaving aside the effects of pressure, yes, the temperatures are the same. But the amount of heat (thermal energy) per gram, is much greater for the steam.
All calculations below are assumed done with all materials (ice, water, and steam) being at normal atmospheric pressure. 3.0kg is 3000 gm. Heat required to raise temperature of ice from -10 degree celcius to 0 degrees celcius is 3000 x 10 cals. (A) The latent heat of fusion of ice is 80 cals per gm. So heat needed to melt 3000 gm of ice at 0 degrees celcius is 3000 x 80 cal. (B) The heat required to convert 3000 gms of water from 0 degrees celcius to 100 degrees celcius is 3000 x 100 cals. (C) The latent heat of vaporization of steam is approximately 540 cals per gm. Hence heat required to convert 3000 gms of water to steam at 100 degrees celcius is 3000 x 540 cals. (D) Now add (A) + (B) + (C) + (D) = 30000 + 240000 + 300000 + 1620000 cals. And that is = 2190000 cals = 2.19 X 10 to power 6 cals.
1320 btu`s
180
One pound of steam at 212 degrees Fahrenheit contains 1150 BTUs of energy.
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It takes 180 BTUs to raise 1 pound of water from 32 degrees Fahrenheit to 212 degrees Fahrenheit to convert it completely into steam. This change in temperature includes heating the water from its freezing point to boiling point, then undergoing phase change from liquid to gas.
To change 10 pounds of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit, you need to supply enough energy to first melt the ice, then heat the water to the boiling point, and finally convert it to steam. This process requires approximately 180 BTUs per pound of ice to melt it, 180 BTUs per pound of water to heat it to the boiling point, and then 970 BTUs per pound of water to convert it to steam. So, for 10 pounds of ice, the total BTUs required would be around 18,300 BTUs.
One pound of steam weighs the same as one pound of water, which is approximately 16 ounces or 0.45 kilograms.
The assumption that the initial temperature of steam is 100 degrees Celsius is generally valid when referring to saturated steam at atmospheric pressure. However, it's important to consider that the temperature of steam can vary depending on the pressure or if it is superheated. Additional information or measurements may be needed to confirm the exact initial temperature of the steam in a specific scenario.
Steam is usually at a temperature of 212 degrees Fahrenheit (100 degrees Celsius) when it forms at sea level.
1 pound of water at sea level can produce approximately 26.8 cubic feet of steam.
The steam point of the Celsius scale is 100 degrees Celsius. At this temperature, water boils and turns into steam.
Steam can reach temperatures of up to 212 degrees Fahrenheit (100 degrees Celsius) when it is produced.
To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.