It depends upon the size of the bags, the density of the sand, and the depth of sand. For example, if the density is 100 lbs/cubic foot, the bags are 50 lbs each, and you want a depth of 1 inch, then:
31.25 sq ft X 1 inch X 1/12 ft/inch X 100 lbs/cubic foot / 50 lbs/bag = 5.2 bags
Better get 6 bags to have enough. If the depth of sand, density of sand, or size of bags is different than what I assumed for this example, then plug your numbers into the equation above.
Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.
Volume required = 95 sq ft * 2 inch = 95 sq ft * 1/6 sq ft = 95/6 cu ft = 15.833... cu ft. So number of bags @5 cu ft reqd = 15.833.../5 = 3.166... bags ie 4 bags.
1 ft = 12 in → 1 in = 1/12 ft Volume required to cover is 90 sq ft × 1 in = 90 sq ft × 1/12 ft = 7.5 cu ft → number of bags = 7.5 cu ft ÷ 0.8 cu ft/bag = 9.375 bags → you need to buy 10 bags
2 inches is 0.167 feet. 266 ft^2 * 0.167 ft = 44.3 ft^3 44.3 ft^3 / 8 ft^3 = 5.54 bags which ~6 bags By the way ft^3 is cubic feet
1.09 cu yards is 29.43 cubic feet and sands weighs 100 pounds per cu ft so you need 2943 pounds. Dide by 50 pounds per bag that is 59 bags
I need one and a haft yards of sand. If the bags hold 2 cu feet how many bags do I need
Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.
3125 sq ft.
400 sq ft at 1 inch = 400x1/12 cu ft = 33.33 cu ft sand weighs 100 pounds per cu ft 33.33 X 100 = 3333 pounds at 50 lb per bag, that is 3333/50 = 66.7 bags
27 1 cu ft bags or 9 3 cu ft bags.
560 bags
Volume required = 95 sq ft * 2 inch = 95 sq ft * 1/6 sq ft = 95/6 cu ft = 15.833... cu ft. So number of bags @5 cu ft reqd = 15.833.../5 = 3.166... bags ie 4 bags.
2000
1 ft = 12 in → 1 in = 1/12 ft Volume required to cover is 90 sq ft × 1 in = 90 sq ft × 1/12 ft = 7.5 cu ft → number of bags = 7.5 cu ft ÷ 0.8 cu ft/bag = 9.375 bags → you need to buy 10 bags
49 bags. The density of loose sand is about 90 lbs/cu. ft. There are 27 cu. ft. in a cu. yard. Therefore 27 * 90 equals a total weight of 2,430 lbs. for a cu. yard of sand. Given 50 lbs. per bag of sand, you divide 2430 by 50 and get 48.6 bags of sand. Round up to 49.
There are 9 cu ft in a yard x 12 = 108 then divide by 2 = 54 bags
The answer would depend on the size of the bags.