It depends upon the size of the bags, the density of the sand, and the depth of sand. For example, if the density is 100 lbs/cubic foot, the bags are 50 lbs each, and you want a depth of 1 inch, then:
31.25 sq ft X 1 inch X 1/12 ft/inch X 100 lbs/cubic foot / 50 lbs/bag = 5.2 bags
Better get 6 bags to have enough. If the depth of sand, density of sand, or size of bags is different than what I assumed for this example, then plug your numbers into the equation above.
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Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.Volume of sand required = 6 ft * 5 ft * 1 ft = 30 cubic feet. A bag = 3 cubic feet so number of bags required = 30/3 = 10 bags.
Volume required = 95 sq ft * 2 inch = 95 sq ft * 1/6 sq ft = 95/6 cu ft = 15.833... cu ft. So number of bags @5 cu ft reqd = 15.833.../5 = 3.166... bags ie 4 bags.
1 ft = 12 in → 1 in = 1/12 ft Volume required to cover is 90 sq ft × 1 in = 90 sq ft × 1/12 ft = 7.5 cu ft → number of bags = 7.5 cu ft ÷ 0.8 cu ft/bag = 9.375 bags → you need to buy 10 bags
2 inches is 0.167 feet. 266 ft^2 * 0.167 ft = 44.3 ft^3 44.3 ft^3 / 8 ft^3 = 5.54 bags which ~6 bags By the way ft^3 is cubic feet
1.09 cu yards is 29.43 cubic feet and sands weighs 100 pounds per cu ft so you need 2943 pounds. Dide by 50 pounds per bag that is 59 bags