If you mean 10 + 6 that's 16 which is 10000 in binary
5
A binary system can represent two distinct states, typically denoted as 0 and 1. Each bit in a binary system can hold one of these two values. When multiple bits are combined, the number of distinct states increases exponentially; for example, an n-bit binary system can represent 2^n distinct states.
To represent an eight-digit decimal number in Binary-Coded Decimal (BCD), each decimal digit is encoded using 4 bits. Since there are 8 digits in the number, the total number of bits required is 8 digits × 4 bits/digit = 32 bits. Therefore, 32 bits are needed to represent an eight-digit decimal number in BCD.
5 bits are 5 binary digits. If they represent a decimal number, then that number can be anything from zero to 31, and can have either 1 or 2 digits.
The number of digits in a binary code depends on the specific representation or value being encoded. Each binary digit, or "bit," can be either 0 or 1. For example, an 8-bit binary code can represent values from 0 to 255 and consists of 8 digits. In general, the number of digits in a binary code is determined by the required range of values or the amount of data being represented.
Binary bits are necessary to represent 748 different numbers in the sense that binary bits are represented in digital wave form. Binary bits also have an exponent of one.
10 bits would be required. 10 bits long (10 digits long) can represent up to 1024.
23 can be represented in binary as 10111 and would therefore require 5 bits to represent.
5
To represent -5 in binary using two's complement, you first need to determine how many bits are required for the positive equivalent, which is 5. In binary, 5 is represented as 101. To accommodate the negative sign, you typically use at least 8 bits for clarity, which would represent -5 as 11111011 in two's complement. Therefore, at least 8 bits are needed to represent -5 in this format.
45 in binary is 101101, so you need at least 6 bits to represent 45 characters.
Count them: 643(10)=1010000011(2)
To determine how many bytes are needed to represent the number 2501, we first convert it to binary. The binary representation of 2501 is "10011100001," which requires 12 bits. Since one byte is 8 bits, you would need 2 bytes (16 bits) to store the value 2501.
18 in binary is 10010 Since 18 can't be written in term of 2 to the power x, the number of bits needed is 5. The answer is 5
A binary system can represent two distinct states, typically denoted as 0 and 1. Each bit in a binary system can hold one of these two values. When multiple bits are combined, the number of distinct states increases exponentially; for example, an n-bit binary system can represent 2^n distinct states.
32
Most digital computers understand two states, represented as binary digits or bits: 0 and 1. These two states correspond to the off and on positions of electronic switches, allowing computers to process and store information using binary code. By combining these bits, computers can represent a vast range of data and perform complex calculations.