6
530 ÷ 40 = 13 10/40 = 13¼ = 13.25
The answer is 13 with remainder 1, or 13⅓ = 13.3 recurring.
13 R 1
13, remainder 1
To find out how many times 40 can go into 210, you divide 210 by 40. This equals 5.25, meaning 40 can go into 210 a total of 5 times, with a remainder. Thus, 40 fits into 210 five times completely.
530 ÷ 40 = 13 10/40 = 13¼ = 13.25
To find out how many times 13 goes into 520, you would divide 520 by 13. The result of this division is 40. Therefore, 13 goes into 520 40 times.
The answer is 13 with remainder 1, or 13⅓ = 13.3 recurring.
13 R 1
13 times with a remainder of 1
It evenly goes in 45 times.
13, remainder 1
3 can go into 40 a total of 13 times with a remainder of 1. This can be calculated by dividing 40 by 3, which equals 13 with a remainder of 1. In other words, 3 multiplied by 13 equals 39, and adding the remainder of 1 gives us the original number, 40.
The number of times 27 goes into 40 can be determined by dividing 40 by 27. When you divide 40 by 27, you get a quotient of 1 with a remainder of 13. This means that 27 goes into 40 one time with a remainder of 13.
40 times.
13 times.
It goes 40 times.