0
Add your answer:
Earn +20 pts
How many sets of 3-digit numbers can be made using 7 numbers and no duplicates within the 3-digit number?
210
How many sets of numbers go into 20?
Three sets
How many different sets of four numbers can you get from six sets of numbers?
6 if order doesn't matter
How many unique sets of 6 can you get from 1 to 28?
It looks like you are asking how many combinations of 6 numbers are there in the 28 numbers 1 through 28. This is known as the number of combinations of 28 things taken 6 at a time. The answer is 28!/(6!22!) (n! means n factorial, which is the product of all the integers from 1 to n). I get 376,740 if I haven't made an error in arithmetic.
Is there a website where you can entry 40 specific numbers and get all sets of 6 combinations?
I doubt it. You can get 7,676,760 different groups of 6 numbers out of a bucket of 40 numbers. No website is going to give you that much output for a single input.
How many 6 numbers combinations can you make from 1 2 3 4 5 6 and you can use multiple combinations and you have 6 sets of 1 - 6 like a briefcase lock?
The answer is 6^6, or 46656.
How can there be in the many 7 combinations can there be in the digits 1 through 9?
If you mean how many different sets of 7 can be made from 9 numbers, the answer is (9 x 8)/2 ie 36.
How many sets of 3-digit numbers can be made using 7 numbers and no duplicates within the 3-digit number?
210
How many 7 number combinations in 10 numbers?
Without repeating any of the numbers (each used once) = 120 unique "sets" of 7 numbers (i.e. 1234567, 1234568, 1234569, 1234560, 1234578, 1234579, 1234570, 1234589, 1234580, 1234590) If the order matters, you have a much larger number of combinations. (see below) Each of the 120 sets can be arranged in 5040 ways. For a set of N numbers, the possible combinations using K numbers is N! / K! x (N-K)! 10! = 3,628,800 7! = 5040 (10-7)! = 3! = 6 The shortcut is (10 x 9 x 8) / (3 x 2) = 720/6 = 120 --- For rearrangement of numbers (ordered sets), there are 604,800 possible numbers N! / (N-K) ! = 10! / 3! = 3,628,800 / 6 = 604,800 --- For unlimited repetition, there are 10,000,000 (1 x 10^7)
How many sets of numbers go into 20?
Three sets
How many different sets of four numbers can you get from six sets of numbers?
6 if order doesn't matter
How many unique sets of 6 can you get from 1 to 28?
It looks like you are asking how many combinations of 6 numbers are there in the 28 numbers 1 through 28. This is known as the number of combinations of 28 things taken 6 at a time. The answer is 28!/(6!22!) (n! means n factorial, which is the product of all the integers from 1 to n). I get 376,740 if I haven't made an error in arithmetic.
How many combinations of 6 numbers are there in 60 consecutive numbers?
Oh, what a happy little question! When you have 60 consecutive numbers and you want to choose 6 of them, you can use a combination formula to find out how many unique sets you can make. In this case, there are 50,063,860 different combinations you can create. Just imagine all the beautiful possibilities waiting to be discovered!
How many sets of 3 consecutive numbers in 12 hours?
There are eight sets of 3 consecutive numbers in 12 hours.
How many times can you get 6 sets of numbers from 1 to 28 what are these sets of numbers?
There are 376740 such sets and you must think me crazy if you think I will list them all!
Is there a website where you can entry 40 specific numbers and get all sets of 6 combinations?
I doubt it. You can get 7,676,760 different groups of 6 numbers out of a bucket of 40 numbers. No website is going to give you that much output for a single input.
How many sets of numbers can you get from he numbers 4 5 6 7?
from the numbers 4567 we can have 24 numbers
