There are 252 combinations.
210
Three sets
If you are referring to the number of ways to select 3 sets of numbers where each set can contain digits from 0 to 9, and assuming that each set can include repeats, there are (10^3 = 1,000) combinations for three sets. If the sets must be distinct and cannot contain duplicates, the calculation would depend on the specific rules for selecting. Please clarify if you meant something different!
6 if order doesn't matter
It looks like you are asking how many combinations of 6 numbers are there in the 28 numbers 1 through 28. This is known as the number of combinations of 28 things taken 6 at a time. The answer is 28!/(6!22!) (n! means n factorial, which is the product of all the integers from 1 to n). I get 376,740 if I haven't made an error in arithmetic.
The answer is 6^6, or 46656.
If you mean how many different sets of 7 can be made from 9 numbers, the answer is (9 x 8)/2 ie 36.
210
Without repeating any of the numbers (each used once) = 120 unique "sets" of 7 numbers (i.e. 1234567, 1234568, 1234569, 1234560, 1234578, 1234579, 1234570, 1234589, 1234580, 1234590) If the order matters, you have a much larger number of combinations. (see below) Each of the 120 sets can be arranged in 5040 ways. For a set of N numbers, the possible combinations using K numbers is N! / K! x (N-K)! 10! = 3,628,800 7! = 5040 (10-7)! = 3! = 6 The shortcut is (10 x 9 x 8) / (3 x 2) = 720/6 = 120 --- For rearrangement of numbers (ordered sets), there are 604,800 possible numbers N! / (N-K) ! = 10! / 3! = 3,628,800 / 6 = 604,800 --- For unlimited repetition, there are 10,000,000 (1 x 10^7)
Three sets
If you are referring to the number of ways to select 3 sets of numbers where each set can contain digits from 0 to 9, and assuming that each set can include repeats, there are (10^3 = 1,000) combinations for three sets. If the sets must be distinct and cannot contain duplicates, the calculation would depend on the specific rules for selecting. Please clarify if you meant something different!
6 if order doesn't matter
It looks like you are asking how many combinations of 6 numbers are there in the 28 numbers 1 through 28. This is known as the number of combinations of 28 things taken 6 at a time. The answer is 28!/(6!22!) (n! means n factorial, which is the product of all the integers from 1 to n). I get 376,740 if I haven't made an error in arithmetic.
Oh, what a happy little question! When you have 60 consecutive numbers and you want to choose 6 of them, you can use a combination formula to find out how many unique sets you can make. In this case, there are 50,063,860 different combinations you can create. Just imagine all the beautiful possibilities waiting to be discovered!
There are eight sets of 3 consecutive numbers in 12 hours.
There are many combinations of three numbers that can add up to 369. One example is 100, 100, and 169. Another combination could be 123, 123, and 123, or even 200, 100, and 69. The specific numbers can vary widely based on the desired values.
I doubt it. You can get 7,676,760 different groups of 6 numbers out of a bucket of 40 numbers. No website is going to give you that much output for a single input.