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How many 4 number combinations are there with 16 numbers?
To calculate the number of 4-number combinations possible with 16 numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n = 16 (the total number of numbers) and r = 4 (the number of numbers in each combination). Plugging these values into the formula, you would calculate 16C4 = 16! / 4!(16-4)! = 1820. Therefore, there are 1820 possible 4-number combinations with 16 numbers.
How many combinantions of 3 numbers can make 39?
13 combinations of 3
How many combinations of 12 numbers are there in 24?
There are 24C12 = 24*23*...*13/(12*11*...*1) = 2,704,156 combinations.
How many 4 number combinations can you make with numbers from1 to 13 with out the numbers repeating?
(13 x 12 x 11 x 10)/(4 x 3 x 2 x 1) = 715 of them
How many number combinations of 6 numbers are possible from 17 numbers?
If they can repeat, then: 17^6=24,137,569 If they can't repeat, then: 17*16*15*14*13*12=8,910,720
How many number combinations for the numbers 1 through four?
1 and 11 and 21 and 31 and 42 and 12 and 22 and 32 and 43 and 13 and 23 and 33 and 44 and 14 and 24 and 34 and 416 combinations
How many combinations can you make with three numbers?
To calculate the number of combinations with three numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of numbers you have to choose from, and r is the number of numbers you are choosing. So, if you have three numbers to choose from, there would be 3C3 = 3! / 3!(3-3)! = 6 / (6*0!) = 6 / 6 = 1 combination.
How many combinations of 6 numbers are there in 42 numbers what are the numbers?
There are 5245786 possible combinations and I am not stupid enough to try and list what they are!
How many 2 digit combinations can be made from 3 numbers combined?
Only three: 12, 13 and 23. Remember that the combinations 12 and 21 are the same.
How many combinations of 8 numbers are there in 56 numbers?
Assuming you meant how many combinations can be formed by picking 8 numbers from 56 numbers, we have:(56 * 55 * 54 * 53 * 52 * 51 * 50 * 49)/8! = (7 * 11 * 3 * 53 * 13 * 51 * 25 * 7) = 1420494075 combinations. (Also equal to 57274321104000/40320)
What 3 numbers make 130?
As a product of its prime factors: 2*5*13 = 130
How many 3 number combinations can be made with 15 numbers?
15 choose 3 = 15!/(3!*(15-3)!) = 15!/(3!*12!) = (15*14*13)/(3*2) = 5*7*13 = 455
