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To find the number of combinations of 3 that can be made from 7 numbers, you can use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). For this case, ( n = 7 ) and ( r = 3 ). Plugging in the values, ( C(7, 3) = \frac{7!}{3!(7-3)!} = \frac{7 \times 6 \times 5}{3 \times 2 \times 1} = 35 ). Therefore, there are 35 different combinations of 3 numbers that can be formed from 7 numbers.

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1w ago

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