100=2*2*5*5 so only 1 combination of 3 nos. r der
9
8C3 = 56 of them
There are 23C3 = 23!/(20!*3!) = 23*22*21/(3*2*1) = 1,771 combinations.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
There are many combinations of three numbers that can add up to 369. One example is 100, 100, and 169. Another combination could be 123, 123, and 123, or even 200, 100, and 69. The specific numbers can vary widely based on the desired values.
9
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
8C3 = 56 of them
There are 23C3 = 23!/(20!*3!) = 23*22*21/(3*2*1) = 1,771 combinations.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
I dont understand what you are asking.
There are many combinations of 5 numbers which would equal 100, for example...50 + 25 + 20 + 3 + 2 = 10050 + 24 + 19 + 4 + 3 = 10096 + 1 + 1 + 1 + 1 =10017 + 33 + 18 + 31 + 1 = 100 and many, many more.
There are: 10C3 = 120
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
There are many combinations of three numbers that can add up to 369. One example is 100, 100, and 169. Another combination could be 123, 123, and 123, or even 200, 100, and 69. The specific numbers can vary widely based on the desired values.
13 combinations of 3