If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.
126 combinations. Remember that the order does not matter.
420
Just one. The order of the element in a combination does not matter.
7 of them. Remember, that in a combination the order of the numbers does not matter.
if you can start with 0, there are 5 x 4 x 3 x 2 = 120 combinations. if you can't start with 0 then 4 x 4 x 3 x 2 = 96 combinations
If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.
126 combinations. Remember that the order does not matter.
999 (whole) numbers. THere are the same number whether they are counted in ascending, descending or other order.
One many find this answer on YouTube. One also may find out how to write ascending order programs using an 8086 microprocessor by looking at the owners manual.
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
10 Combinations (if order doesn't matter). 3,628,800 Possiblilities (if order matters).
You can get only four combinations: They are: 11, 118, 119 and 1189. In a combination, the order of the digits does not matter.
420
The question contradicts itself. The order of the letters is irrelevant in a combination [though it does matter in a permutation]. So what is it that you are asking for? Combinations or order-dependent arrangements?
45 In combinations, the order of the digits does not matter so that 12 and 21 are considered the same.
To calculate the number of 4-digit combinations using the digits 1, 3, 5, and 7 exactly once each, we can use the permutation formula. There are 4 choices for the first digit, 3 choices for the second digit, 2 choices for the third digit, and 1 choice for the fourth digit. Therefore, the total number of combinations is 4 x 3 x 2 x 1 = 24. So, there are 24 possible 4-digit combinations using the digits 1, 3, 5, and 7 exactly once each.