You can get only four combinations:
They are: 11, 118, 119 and 1189.
In a combination, the order of the digits does not matter.
There are: 9C6 = 84 combinations
If the numbers are allowed to repeat, then there are six to the fourth power possible combinations, or 1296. If they are not allowed to repeat then there are only 360 combinations.
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
Oh, isn't that a happy little question? Let's see here... To find the number of combinations of 4 numbers out of 7, we can use a simple formula: 7 choose 4, which is calculated as 7! / (4! * (7-4)!). So, there are 35 unique combinations of 4 numbers that can be made from a set of 7 numbers. Isn't that just delightful?
There are 167960 9 digits combinations between numbers 1 and 20.
The answer is 10C4 = 10!/[4!*6!] = 210
There are 840 4-digit combinations without repeating any digit in the combinations.
There are 35C4 = 35*34*33*32/(4*3*2*1) = 52,360 combinations.
Including the leading zero, then the answer is 210. Or, allowing for repeating numbers, 10000.
There are: 9C6 = 84 combinations
11
There are 167960 combinations.
There are 125970 combinations and I am not stupid enough to try and list them!
There are 10,737,573 combinations and you must think I am mad if you think I am going to list them!
Not repeating, it is 7*6*5*4 which is 840 ways ---- There are 7 choices for each of four digits, right? 74 = 2401
There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.
252 combinations, :)