2334
4332
3324
3342
There are 8*7/(2*1) = 28 combinations.
There are 11C2 = 11*10/(2*1) = 55 combinations.
There are 21 combinations.
none
There are 9C2 = 9*8/(2*1) = 36 2-digit combinations.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 8*7/(2*1) = 28 combinations.
Only three: 12, 13 and 23. Remember that the combinations 12 and 21 are the same.
There are 11C2 = 11*10/(2*1) = 55 combinations.
There are 21 combinations.
none
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
There are 45 combinations.
There are 233 - 1 = 8,589,934,591 combinations, not including the null combination.
There are 9C2 = 9*8/(2*1) = 36 2-digit combinations.
This questions can be rewritten as 52 choose 6 or 52C6. This is the same as (52!)/(6!(52-6)!) (52!)(6!46!) (52*51*50*49*48*47)/(6*5*4*3*2*1) 14658134400/720 20358520 There are 20,358,520 combinations of 6 numbers in 52 numbers. This treats 1,2,3,4,5,6 and 6,5,4,3,2,1 as the same combination since they are the same set of numbers.