The answer is 10C4 = 10*9*8*7/(4*3*2*1) = 210 ways.
The answer is 10C4 = 10!/[4!*6!] = 210
Allowing repeats, but not leading 0s, the answer is 9,000,000,000
9
There are a total of 1,000 three-digit combinations from 000 to 999. This includes all combinations where the digits can range from 0 to 9, allowing for repetitions. Each of the three digit positions can have 10 possible values (0-9), leading to (10 \times 10 \times 10 = 1,000) combinations.
10C6 = 10*9*8*7/(4*3*2*1) = 210 combinations.
45
10
"There are 10,000 different combinations"-Hey nick! love dave and jalp
10
10 Combinations (if order doesn't matter). 3,628,800 Possiblilities (if order matters).
The answer is 10C4 = 10!/[4!*6!] = 210
10*10
Allowing repeats, but not leading 0s, the answer is 9,000,000,000
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.
9
There are a total of 1,000 three-digit combinations from 000 to 999. This includes all combinations where the digits can range from 0 to 9, allowing for repetitions. Each of the three digit positions can have 10 possible values (0-9), leading to (10 \times 10 \times 10 = 1,000) combinations.
10C6 = 10*9*8*7/(4*3*2*1) = 210 combinations.